View Single Post
  #8  
Old December 12th 12, 09:04 AM posted to uk.sci.astronomy
Szczepan Bialek
external usenet poster
 
Posts: 51
Default Planet's density


"Barry Schwarz" napisal w wiadomosci
...
On Tue, 11 Dec 2012 09:53:39 +0100, "Szczepan Bialek"
wrote:

We know the GM only. The G (gravitational constant) was mesured by
Cavendish
on the Earth surface where is the excess of electrons.


For some reason you think the electrons have some effect on the
measurement of G. Since the Earth has more water than the moon or
Mars, maybe that affects the measurement of G also.

On the Moon is the electrostatic levitation of the dust.
So the G may be incorrect. It is possible that the planets do not have
metal
cores.


The supposition is the gas giants don't.


If "the electrons has some effect on the measurements of G" than the
terrestial planets also do not.
The only "cause" of the metal core is the calculated density 5.5.

It would be interested to know the measurements done on the ISS. ISS is a
"planet" which mass is known and not small.


Compared to almost any other non-manmade object, the mass of the ISS
is quite small.


But bigger than the Cavendish masses.

Does ISS attract the cosmonauts or repel them?


And it would repel them because?


Everything in the space have the excess of electrons. In such case the small
objects repel. Like the dust and fog (water droplets) in the air.

The gravitational force between two
objects is proportional to the product of their masses. There is no
**noticeable** attraction between the ISS and the supply ships that
dock with it periodically. The mass of the supply ship is orders of
magnitude more than the mass of a cosmonaut. The attraction between
the ISS and a cosmonaut would therefore be orders of magnitude less.


And the repulsion is prportional to the charges.
What is the netto force between the ISS and a supply ship?
Between the dust particles the repulsion is the winner.
S*