The Feynman Lectures on Physics, Volume 2, Chapter 42-6:
"Suppose we put a clock at the "head" of the rocket ship - that is, at
the front end - and we put another identical clock at the "tail," as
in fig. 42-16. Let's call the two clocks A and B. If we compare these
two clocks when the ship is accelerating, the clock at the head seems
to run fast relative to the one at the tail. To see that, imagine that
the front clock emits a flash of light each second, and that you are
sitting at the tail comparing the arival of the light flashes with the
ticks of clock B. (...) The first flash travels the distance L1 and
the second flash travels the shorter distance L2. It is a shorter
distance because the ship is acelerating and has a higher speed at the
time of the second flash. You can see, then, that if the two flashes
were emitted from clock A one second apart, they would arrive at clock
B with a separation somewhat less than one second, since the second
flash doesn't spend as much time on the way."
Einsteiniana's idiocies can confuse any mind, even Richard Feynman's
one! If the acceleration is uniform, it is obvious that L1=L2.
The problem has an easy solution. The observer (sitting at the tail)
measures the frequency of light to have increased. Then, by taking
into account the formula:
(frequency) = (speed of light)/(wavelength)
he concludes that either the speed of light (relative to the observer)
has increased (then Einstein's 1905 light postulate is false) or the
wavelength has decreased. Einsteinians believe that the wavelength
somehow varies with the speed of the observer:
http://www.pitt.edu/~jdnorton/teachi...ang/index.html
John Norton: "Here's a light wave and an observer. If the observer
were to hurry towards the source of the light, the observer would now
pass wavecrests more frequently than the resting observer. That would
mean that moving observer would find the frequency of the light to
have increased (AND CORRESPONDINGLY FOR THE WAVELENGTH - THE DISTANCE
BETWEEN CRESTS - TO HAVE DECREASED)."
Pentcho Valev