On 5/30/2017 6:55 AM, Phillip Helbig (undress to reply) wrote:
A smooth distribution corresponds to high entropy and a lumpy one to low
entropy if gravity is not involved. For example, air in a room has high
entropy, but all the oxygen in one part and all the nitrogen in another
part would correspond to low entropy.

If gravity is involved, however, things are reversed: a lumpy
distribution (e.g. everything in black holes) has a high entropy

But if everything is in one big black hole, and the black hole
would need only mass and angular momentum and charge to describe
it, then that would be extremely low entropy (and essentially we
would have back the "ordinary" behavior you described first).

So the difference is only in the entropy that is in the "soft
supertranslation hair" (if that is the correct theory..)

If the oxygen in one corner of the room would also have this
extra entropy that black holes seem to have (for whatever reason),
then the cases would be the same.

Provided of course that before black hole formation occurs
the normal behavior (lumpy distribution has lower entropy) is
respected by gravity as it is by other forces. So the question
is: would there still be a reason, in cases without black holes,
to expect that gravity is different?

--
Jos