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Old December 1st 06, 01:47 PM posted to sci.physics.relativity,sci.physics,sci.astro
jem[_1_]
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Default Interpreting the MMX null result

kenseto wrote:

"jem" wrote in message
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kenseto wrote:

"jem" wrote in message


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kenseto wrote:


"jem" wrote in message
...



kenseto wrote:




"jem" wrote in message


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kenseto wrote:





"jem" wrote in message

locations?


All locations on earth share the same absolute motion.

So then it must be the case that *all* MMX devices which are attached to
the surface of the Earth, share the same absolute motion (i.e. speed and
direction) at their points of attachment. Right?


But the MMX is designed only to test the isotropy of the speed of light.


and this causes the isotropy and anistropy of the speed of



light detected by the horizontal and vertical MMXs.


Anistropy of the speed of light is caused by the source and the


detector

have different states of absolute motion.


And the reason that no previous MMX has detected anisotropy is because
the source and detector have always shared the same absolute motion.

Right?

Sure.....but vertical MMX will detect anisotropy because the two light


rays

are emanated from the reflecting mirrors at different heights (thus
different state of absolute motion)


And the absolute motion shared by the source and detector has always
been perpendicular to the plane defined by the arms of the MMX devices.
Right?


Again the MMX is not designed to detect absolute motion of the earth. It


is

designed to detect the isotropy or anistropy of the speed of light.



Don't worry about what the MMX is designed to test - just answer the
one-word questions.

So then it must be the case that *all* MMX devices which are attached to
the surface of the Earth, share the same absolute motion (i.e. speed and
direction) at their points of attachment. Right?



Speed and direction of absolute motion wrt what?


Speed and direction wrt anything.



And the absolute motion shared by the source and detector has always
been perpendicular to the plane defined by the arms of the MMX devices.
Right?



NO.....if the MMXZ detected isotropy then it is perpendicular to the plane
frined by the arms of the MMX.


and just how do you think that differs from what I said?