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Old February 28th 05, 03:36 PM
Robert Clark
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s= 1/2 * a * t^2
The acceleration is given in the calculation:

s= 1/2 * a * t^2,

37.5E9 = 0.5 x a x (608000)^2 = 0.5 x a x 3.7E11 ,
so a = 0.2 m/s^2 .

This is 1/50 of normal Earth gravity of 9.8 m/s^2. So a 200 pound man
would weigh only 4 lbs. This could be a problem over a long mission but
not on a trip of only two weeks duration.

Bob Clark