On Mon, 5 Jan 2009 23:54:30 -0800 (PST), Koobee Wublee
wrote:

On Jan 5, 11:48 pm, George Hammond wrote:
Koobee Wublee wrote:

No, you can say “SUBSTITUTE” (r + K) for R. shrug

In that case, the two said geometries of spacetime a

** ds1^2 = c^2 (1 – K / r) dt^2 – dr^2 / (1 – K / r) – r^2 dO^2

** ds2^2 = c^2 (1 – K / R) dt^2 – dR^2 / (1 – K / R) – R^2 dO^2

In that case, they are still very different where (R = r + K).

[Hammond]
The COORDINATES are different, but the METRIC is the same.

No, the coordinates are different:

[Hammond]
That's what I just said, you're repeating yourself Koobic.

** (r, theta, phi)
** (R, theta, phi)

Where

** R = r + k

The metric is the Schwarzchild metric in BOTH cases.
You don't know the difference.

No, the metrics are also different.


[Hammond]
NO.... the metrics are NOT different. They both describe
the SAME physical space with the same metrical distances.
The space described by (r,theta, phi) is IDENTICAL to the
space described by (R,theta,phi) because the METRICS are
identical, irregardless of what K is...a Titleist golf ball
is exactly the same diameter and shape whether it is
described by R or r...in fact both spaces are identically
Schwarchild space. Obviously you have no credentials in
Physics.
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This is basic mathematics. Try
to understand mathematics in grade school. shrug

[snipped diarrhea of Einstein Dingleberries]