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Old December 13th 03, 04:30 PM
Jonathan Silverlight
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Default Astronomers Re-measure the Universe with Hubble Space Telescope (Forwarded)

In message , Aladar
writes

Now, on the other hand, there is a perfectly good, coherent
representation of matter structure [a candy for the correct answer!]
which results in the photon energy loss with an exponential to
the distance rate - z =2^(t/Hd)-1 where t is the time of photon
travel and Hd =4.111 bly Hubble photon wavelength doubling time
constant. It is around 170 km/s per Mpc for the linear approximation
for very small redshifts.


I thought your figure was Hd = 4.234 billion
years. Given that you're quoting it to 4 decimal places, isn't that a
rather large difference?
--
Rabbit arithmetic - 1 plus 1 equals 10
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