"Brad Guth" wrote in message
news:5a1b490b9c00901053006a1a57fd7180.49644@mygate .mailgate.org

If tidal forces and/or whatever amount of mass that's leaving our moon
is what's causing the ongoing recession of 38 mm/year, whereas our moon
simply has to be running a touch slower due to its having to cover more
ground each year, and that's not including the likelihood of actually
having lost velocity in the process of overcoming the Vt/slug factor of
space travel for having such a rough surface area of 40e12 m2 to deal
with.

Is there actually enough secondary tidal energy alone, as to otherwise
not losing time by way of having increased the velocity of our moon by
0.451 meter/year?

Using E=MV2

7.35e22 * .2034 = 1.495e22

1.495e22 joules of such tidal energy as made available per year:

14.95e21/3.15576e7 = 473.737e12 joules of continuous applied energy.

So the real question is: how much time is the moon losing per year?

Once we know for certain, of what it's taking to motivate our moon as
is, whereas perhaps then the next phase of devising upon methods of
relocating our moon out to Earth's L1 can be mastered.
-
Brad Guth


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