This has all been discussed recently in two other
threads but Max seems to want to repeat all his
mistakes again:

Max Keon wrote:
....
The equation representing an upward moving mass relative to a
gravity source is ((c+v)^2/c^2)^.5*G*M/r^2-(G*M/r^2),

This can be more easily written as

a = (v/c) * (GM/r^2)

Assuming we are using polar coordinates and v is
the radial component of the velocity, we have:

v = dr/dt

hence since the speed is positive, the acceleration is
also positive and the moving mass will be accelerated
away from the larger mass M and gain energy.

However, Max later seems to suggest v could be the
velocity since he says "matter will be slowed in the
direction of motion" rather than towards the mass M.

.. while
((c-v)^2/c^2)^.5*G*M/r^2-(G*M/r^2) represents a downward moving
mass.

This can be more easily written as

a = -(v/c) * (GM/r^2)

For a mass moving towards M, v is negative so again
the acceleration is outward and this time the mass
is slowed and loses energy.

... The
moving matter will be slowed in the direction of motion according
to a combination of the two equations.

The equations describe slowing for an inward moving
mass but increasing speed for an outward moving
mass.

I'll snip the stuff on Mercury until Max decides whether
the acceleration is towards mass M or opposes the
direction of motion.

Pioneer

For Pioneer, the two directions are similar so we can look
at Max's numbers:

... The Universe alone is responsible for the
anomalous acceleration which appears to be directed toward the
Sun.

((c+v)^2/c^2)^.5 * (G*M/r^2) - (G*M/r^2) = 8.34E-10 m/sec^2.

However, the anomalous acceleration of Pioneer 10 is
-8.74E-10 m/s^2 hence in the opposite direction. This
has already been pointed out to Max.

Pioneer 10 is following a path which is close to 11 degrees off
a line through the Sun, and its velocity is slowed by 8.4E-10
m/sec^2 along that line, while it's also being deflected at that
same rate perpendicular to that line.

Using Max's figure of 8.34E-10 m/s^2, the above
equations give a radial component of 8.19E-10 m/s^2
for either interpretation of the direction (a factor of
cos(11) applies either in deriving v or finding the
radial component of a). The tangential component is
zero if the direction is taken as being towards the Sun
or 1.59E-10 m/s^2 (a factor of sin(11) if it opposes the
direction of motion. The "same rate perpendicular to
that line" is wrong either way.

George