This post is stored along with the images at
http://www.optusnet.com.au/~maxkeon/pionomor.html
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Pioneer Anomaly Anomalous No More.
The story unfolds as a direct consequence of a universe which
came into being from absolutely nothing,
http://www.optusnet.com.au/~maxkeon/the1-1a.html a zero origin
universe in fact. In that universe, light doesn't actually
propagate anywhere, but it does move relative to a base that is
set by the combined input from all local matter, anywhere, i.e.
the Earth. According to the laws of that universe, the entire
dimension surrounding every bit of matter in the universe is
shifting inward into its own gravity well at the rate of
(G*M/r^2)*2 meters in each second and is updated at the speed of
light. Meaning that its acceleration capability diminishes to
zero for anything moving at light speed toward its center of
mass. The shift rate of dimension is necessarily twice the shift
rate of the matter that the moving dimension carries along with
it, otherwise there would be no driving mechanism available to
perform the task.
The equation representing an upward moving mass relative to a
gravity source is ((c+v)^2/c^2)^.5*G*M/r^2-(G*M/r^2), while
((c-v)^2/c^2)^.5*G*M/r^2-(G*M/r^2) represents a downward moving
mass. Even matter in a fixed position relative to a gravity
source is traveling outward through dimension because dimension
is traveling inward through it, hence the action of gravity.
Another consequence of the velocity related gravity anisotropy
is that any motion anywhere in the universe is going to be
affected by every bit of matter in the universe to some degree.
While matter is fixed with the local base of dimension it's not
traveling anywhere relative to the universe, but as soon as it
moves, it's moving into an all pervasive wall of resistance that
is forever present in the direction of relative motion. The
moving matter will be slowed in the direction of motion according
to a combination of the two equations.
Assuming that Mercury has just arrived at its average orbit
radius and is traveling at 48000m/sec around a circular orbit
path, these are the numbers for the universe generated
anisotropy; ((c+v)^2/c^2)^.5*G*M/r^2-(G*M/r^2) : v=48000:
G=6.67E-11: M=300000: r=1. 300000kg of matter at 1 meter radius
is the same ratio as taking the mass of all matter in the visible
universe in the direction of relative motion (3.45E+53kg), at its
respective radii, and then combining them. It gives a slowing
rate for Mercury's orbit velocity of 3.19E-9 meters in each
second.
http://www.optusnet.com.au/~maxkeon/piondat.html This 600k
byte data file was generated from calculating the input to the
anisotropy from the universe where the effective mass of the
universe in the direction of relative motion is integrated over
3988 equally spaced 1 MPc steps, right back to where the
universe disappears from view. The mass housed in each step is
reduced until it becomes zero for the final step at the 13
billion light year distance.
The shell widths remain constant only from our viewpoint. Due to
the expansion (in the big bang universe) the shell widths are in
fact becoming increasingly narrow per distance. If they were made
to expand along with the expansion, each shell would contain
exactly the same amount of matter because the expansion is not
just along the line to the edge of the visible universe, it's 3D.
But the number of shells would be significantly reduced.
The first step is the most significant, contributing more than
half that from the entire universe. Matter is least homogeneously
distributed within that step. But it's not a concern if the
anisotropy isn't generated isotropically throughout an orbit
cycle anyway. Even so, the contributions from Andromeda and the
Alpha Centauri group don't contribute significantly to the
gravity anisotropy, and they would represent the most significant
local influence.
Mercury's motion relative to the mass of the universe sets up a
wall of resistance which shortens its travel distance by 3.19E-9
meters in 1 second. But there is no physical link between the
moving Mercury and the matter of the universe where the missing
distance can be justified. It's not possible for the matter of
the universe to shift to accommodate any change in momentum over
the time span of Mercury's orbit. The only means of transferring
energy in that direction is through gravitational radiation,
which is nowhere near up to the task. So it must be accounted
for locally.
If during the 1 second (48000 - 3.19E-9) meter journey along the
orbit path, Mercury is deflected by 3.19E-9 meters, squarely
across the invisible face of the perpetual wall of resistance,
initiated to point toward the Sun by its curved orbit path, the
addition of the distance traveled in the two planes is still
48000 meters.
The obvious reaction to that claim is that Mercury's actual travel
distance is a^2+b^2=c^2 = sqr((48000 - 3.19E-9)^2 + 3.19E-9^2)
which is virtually unaltered from the shortened but undeflected
path. The problem is that the simple linear measurements that
apply in the realm of matter don't apply in the 3D realm of
gravity. All measurements in that realm must necessarily include
the three dimension which are perpendicular to each other.
Mercury moves (48000 - 3.19E-9) meters in 1 second through two
planes of dimension. And it's deflected by 3.19E-9 meters toward
the Sun in two planes of dimension. The equation for the triangle
becomes a+b=c. The lengths are already squared.
Mercury's fall to the Sun will be halted when centrifugal forces
overcome the inward driving force generated by the anisotropy.
Mercury would then just cycle around within the background
universe as if it was housed at the center of some gigantic
elastic web.
http://www.optusnet.com.au/~maxkeon/merc-un.gif The set of
oscillating rings that reduce in oscillation magnitude per
distance from the orbiting Mercury (red circle), depict how
Mercury's motion will oscillate around within the background
universe. The scale is far from accurate. It's very compressed
toward the outer edge. Over each 88 day orbit cycle, one
compression-rarefaction wave will be sent off throughout the
plane of the orbit, into the universe. There will be around 18
of them between here and our nearest neighbor. The force in the
anisotropy generated by the universe is obviously very flexible
over the time span of Mercury's orbit. There is virtually no
direct link between Mercury and any part of the universe.
The black line through the orbit axis is the perpetual wall of
resistance from the universe generated gravity anisotropy. But
over the time span of Mercury's orbit cycle, that can be of very
little consequence.
When Mercury finally arrives at a stable orbit radius, it is
orbiting faster than would be expected from simple Newtonian
gravity. i.e. The Sun is less massive than we think it is. If
the mass of the Sun is .999978 of the presumed value, which
camouflages the Pioneer anomaly for the close to the Sun
case, Mercury would be traveling a 627 kilometer longer orbit
radius than it should be for its velocity. It's moving at the
correct rate for the more massive Sun, but is faster than it
should be for the true Sun's mass.
The universe generated gravity anisotropy doesn't end at Mercury
of course, it extends throughout the universe. The fact that
centrifugal forces between a galaxy center and the stars in its
outer region alter according to 1/r instead of 1/r^2 is an
excellent indication that a gravity anisotropy is present.
The anisotropy drives the star inward toward the galaxy center,
until centrifugal forces build to counteract the fall. The
anisotropy is directly proportional to velocity, while the
centrifugal force alters according to v^2, thus the fall is
halted. The star will now be traveling faster than it should be
for the orbit radius. There is obviously a good reason why it
stops falling where it does.
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Pioneer
The Sun is only the catalyst which initiates Pioneer's
deflection direction. The Universe alone is responsible for the
anomalous acceleration which appears to be directed toward the
Sun.
((c+v)^2/c^2)^.5 * (G*M/r^2) - (G*M/r^2) = 8.34E-10 m/sec^2.
is the Pioneer anomaly for 12500m/sec velocity, which would be
expected to be fairly constant right up to the Sun if the same
velocity was maintained. This graph was generated using the
lighter Sun (1.989957E+30kg).
http://www.optusnet.com.au/~maxkeon/pioneer1.jpg
The next graph was generated using the more massive Sun
(1.99E+30kg), which partly conceals the combined Sun and universe
generated anisotropies nearer to the Sun. But it's obviously not
possible to conceal them both for all distances.
http://www.optusnet.com.au/~maxkeon/pioneer2.jpg
The Sun's gravity error at a radius of 20AU from the Sun is
GM/r^2 for a Sun mass of 1.99E30 minus GM/r^2 for a Sun mass of
1.989957E+30 = 3.19E-10m/sec^2. Each graph is reduced by that
amount at that radius. And so on for the rest of each curve.
Pioneer 10 is following a path which is close to 11 degrees off
a line through the Sun, and its velocity is slowed by 8.4E-10
m/sec^2 along that line, while it's also being deflected at that
same rate perpendicular to that line. Pioneer's trajectory is
curving toward the Sun at the rate of TAN-1(8.4E-10 / 12500)
= 3.85e-12 degrees per second, or 1.214e-4 degrees per year.
The combination of those two trajectory changes is going to look
very much like a direct fall to the Sun.
-----
Max Keon