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Old April 6th 06, 05:12 PM posted to sci.astro
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Default Keplerian Trajectory

Llanzlan Klazmon wrote:
wrote in news:1144244869.312028.216920
@v46g2000cwv.googlegroups.com:


What is it?

Thank you,
Christopher Lusardi



I'm not sure that Bill's explanation is quite right. Historically, a
Keplerian trajectory would be a segment of a Keplerian orbit as described
by Keplers first law. This means a segment of an ellipse (or circle as a
circle is just an ellipse with zero eccentricity). The other conic sections
mentioned, a parabola or hyperbolia, which are also solutions to Newton's
laws for a two body problem involving gravity would not qualify, as Kepler
himself did not know of such orbits.

Klazmon.


A bit of a nit, you'll admit, but I'm hit.

I accept your correction; thanks.

-- Bill