In article .com,
"newedana" wrote:
It is quite certain electric and magnetic forces can act through vacant
vacuum space without any mass mediation. Thus the light wave generated by
orbital electron rings, can propagate through the vacant empty space in radial
symmetric around them, constructing milliards of concentric spherical wave
fronts with equi-energy level. In consequence, it has to have a constant speed
anywhere in this cosmic space since the vacuum space itself is the medium of
light propagation, and the medium has an absolutely isotropic physical
character.

1. All the wave fronts produced by oscillation of orbital electron
rings, or the orbital electron building a tiny persistent current ring
around its nucleus, expand their spherical radii infinitely as they
propagate through the vast space of this universe. However, the energy
of each wave front does not change depending on whatever the magnitude
of their spherical radii. All the successive wave fronts have exactly
the same energy as that of orbital electron rings performing a half
cycle of their oscillation, or

E=S1ε1=S2ε2=S3ε3=. . . . .=Sn εn

Where E: energy of an orbital electron ring oscillating a half cycle,
S1,S2,S3.......Sn: surface areas of sequential spherical wave fronts,
and ε1, ε2 ε3 .......εn : energy densities of each wave fronts.
Since Sn/S1=n^2, and n: integer, the intensity of a light beam
decreases by inverse square distance rule. We may find that the energy
dispersion occurs not only along the proceeding direction of light but
also in perpendicular direction to their advancing direction, along
their wave crests and troughs.

This fact tells explicitly that light emission and its propagation is
nothing else than the equilibrating process of electromagnetic energy
of oscillatory electron rings in the light source through the vacant
cosmic space, and not the process of Einstein's space travel of photons
with their momentum given by their source.

2. If we put an optical shield on the pathway of above spherical wave
fronts, a shadowy space is made possible behind it. What happens there?
The light pencils

I do hope they're #2.

at the edge of the shield bend inward to the shadowy
space, due to the dispersing energy pressure of spherical wave fronts
undestroyed. The higher the frequency and intensity of light the
greater the bending curvature of light, and vise versa. This is the
mechanism of light diffraction that was not yet fully understood up to
the present.

And is still not by you.


3. A light beam is nothing but a thinly sliced sections of these
spherical wave fronts along their concentrical arrangements in their
propagating direction. Since it is not a flow of corpuscular photons,
the interpretation of double slit experiment by Dr. Yoon's new physics
is consequently quite different from current understanding.

Sure, just like interpreting chemical bonding as tiny gremlins holding hands
would be quite different from current understanding.


If a plane wave front (wave front of light beam) is slitted by two tiny
apertures, there made two light beams which turn out to develop into
two spherical waves, A and B, due to the energy flow of light along the
wave crest and trough.

When the first wave phase of spherical wave A interferes with the same
first wave phase of spherical wave B it constructs the 0th order of
diffraction light with the most intensive one. If the second wave
phase of wave A interferes with the first wave phase of wave B it
builds the 1st order of diffraction light with a lesser intensity. The
same 1st order of diffraction light is made possible at symmetrical
positions between first wave phase of wave A and second wave phase of
wave B. With the same way, two diffraction lights of 2nd order with
more lesser intensity are made possible between third wave phases of A
light and first wave phase of B light, and between first wave phase of
A light and third wave phase of B light, and so on. This is the correct
understanding of two slit experiment of light. The interpretation with
probability statistics of falling photons on screens is nonsense and a
magic story.

4. In the spherical wave front the light pencil in the center proceeds
along a straight path without bending while other outer light pencils
turn out to bend with their respective curvatures that change depending
on their deviation from the center light pencil, due to the energy flow
along their crests and troughs. The farther the deviation from the
center the greater the curvature of light pencils,

Do they ever need refills?

and vice versa.
However, all the pathway length of curved light pencils is exactly the
same as that of straight light pencil since the speed of light is
always the same and constant.

Atomic nuclei building material system act to slit wave fronts of
incoming light to build numerous spherical waves. For example, when the
above two spherical waves built by slitting the plane wave front,
interfere constructively within their half wavelengths, or Dλ/2, a
single wave beam of 0th order with different preceeding direction, can
be built if incident angle is not zero. This is the case of light
refraction.

Dr.Yoon's textbook (www.yoonsatom.net) explains how the light
refraction takes place between different materials with different
optical density. He built a simple equation representing the light
refraction without setting up any postulations or premises, which
involving no speed term. It has the form,

n=(φ/sinφ) secηΔθ

where φ=2k/λ, k: spacing parameter between atomic nuclei (mass
density factor), λ: wavelength of incident light, θ: incident angle,
η: a constant.

This equation is simply derived by due analytical process of optical
geometry and rule of trigonometry. The parameter k representing mass
density governs the bending curvatures of light pencil passing through
material system, the greater the value the larger the curvature.
Wavelengthλrules out also the roundly bending curvature of light
pencil through material system, the greater the wavelength the smaller
the bending curvature ( the reason is in his text).

However if the spacing of aperture is over one wavelength there
occurs multiple wave interference between sequential wave phases of
these two spherical waves. So a large number of light beams can be
made. It is the case of light diffraction mentioned above.

5. How can electrons be ejected in the Photoelectric experiments if
light is just wave?
In Dr. Hansik Yoon's New Physics (www.yoonsatom.net), orbital electron
of atom builds a micro persistent current ring around its nucleus.

So something would have to be circulating around the nucleus. How come we
detect nothing?

When
this atomic orbital electron ring receives an electromagnetic radiation
whose frequency resonates to its inherent frequency, it takes up wave
energy and oscillates with the same frequency but with a larger
amplitude.


Sounds like you're still using the "miniature solar system" model.

However if it receives an electromagnetic radiation of a higher
frequency but with non-resonant frequency, its ring form turns out to
be broken and liberates the electron with its revolving kinetic energy
that makes the photo-electric current. The shorter the radii of the
electron ring, the higher the energy required to break it and the
higher the kinetic energy of liberated electron.

It is well known that alkali metals are very sensitive in Photoelectric
Effect, because they have the outermost electron rings with the weakest
tenacity against bombardment of radiation energy.

X-rays and gamma rays can also break the outermost electron rings of
atoms to ionize them, since these rays are difficult to be resonate to
the frequency of orbital electron rings of atoms, and have a far
greater energy level. newedana