newedana wrote:
The energy emission taking place when orbital electron rings expand, can=
be observed in the case when chemical explosives such as TNT (trinitrotolu=
en) explodes. The outermost orbital electron rings of their component atoms=
contributing to combine them, expand only a little bit in this case of exp=
losion, due to dissociation of TNT to form various kinds of gas molecules, =
such as H2O, CO2, and NO2 etc.

It is well known that the explosion of only about 7 kgs of uranium 235 p=
roduces such an enormous energy equivalent to that emitted by explosion of =
TNT 20,000 metric tons. The mass ratio of these two explosive materials is=
about, 1 : 2.86x10^6. If the orbital electron rings in K shell of uranium =
atom with radial parameter, say, =CE=B3=3D1/100, expands to be the orbital =
electron rings in K shell of newly created atoms that has radial parameter,=
say, =CE=B3=3D1/99.28, then the ratio of energy capacity of these two orbi=
tal electron rings becomes the same as the mass ratio, 2.86x10^6 , as shown=
above when we estimate it with Eq.=E2=96=B3E=3DE'(1/r^4, previously posted=
.. The difference of radial parameter between these two electron rings is n=
egligibly small, or =CE=94=CE=B3=3D1/99.28-1/100=3D1/13,789, but the ratio =
of their energy capacity is enormous, as shown above. However, this energy =
emission comes only from the expansion of orbital electron rings in K shell=
of uranium 235. Other orbital electron rings in L, M, N,. . . .shells of u=
ranium 235 would also have to expand their orbital radii emitting huge ener=
gies also as in the case of electron rings of K shell. Thus the explosion o=
f only 7 kg of uranium 235 gives rise to producing such a tremendous energy.

The fundamental mechanism of emitting energy from nuclear fusion of deut=
erons is exactly the same as that of nuclear fission of uranium 235. It is =
also the expanding energy of electron rings. In the case of nuclear fission=
atomic electron rings expand, while in the case of nuclear fusion nuclear=
electron rings associated in the structure of two deuterons expand, emitti=
ng nuclear energy. When nuclear electron rings of two deterons combine to b=
uild a unified nuclear electron ring with pair electrons, they have to expa=
nd their orbital radii emitting energy, in order to bind four protons to bu=
ild two neutrons and two protons in a helium nucleus. This is the nuclear f=
usion energy. It is the same as that when two hydrogen atoms combine to for=
m a hydrogen molecule having molecular electron rings carrying pair electro=
ns, with their two single atomic electron rings, emitting energy.
A single nuclear electron ring that binds two protons in constructing a =
neuteron, can emit =CE=B3-rays at the nearest distance to its two nuclear p=
rotons when it breaks. Since this single nuclear electron ring can emit =
=CE=B3-rays with wavelength 0.005 =E2=84=AB, its radial parameter must be, =
=CE=B3=3D1/430, when we estimate it with the same equation, =E2=96=B3E=3DE'=
(1/r^4) I posted above. If these single nuclear electron rings expand their=
orbital radii and emit energy equivalent to that energy given by explosion=
of 7 kgs of uranium 235, their radial parameter has to expand from =CE=B3=
=3D1/430 to =CE=B3=3D1/429.991. The distinction between them is, =E2=96=B3=
=CE=B3=3D1/429.991-1/430=3D1/20,544,014. It is an awfully small expansion c=
ompared to that in the case of nuclear fission. However the energy emission=
in the process of nuclear fusion is the same as that in the case of nuclea=
r fission. The ratio of atomic volume of deuterium and helium is, D : He =
=3D 14.1 : 31.8. The larger atomic volume of helium than deuterium is attri=
buted to the reason that the helium nucleus is stabilized in the lowest ene=
rgy level than deuteron. Nuclear fusion energy includes also the energy of =
orbital electron rings of deuterium when they expand their orbital radii to=
be those of helium. newedana