On Wed, 22 Oct 2003 18:05:46 GMT, in a place far, far away, "James
Oberg" made the phosphor on my monitor
glow in such a way as to indicate that:

If S = 0.5 a t**2,
and V = at,

Then since S = 55 ft, and V = 1100 ft/sec

a t**2 = 110
and
at = 1100

gives t= 1/10 sec
a = 11000 ft/sec/sec
where g = 32.2 ft/sec/sec
hence a = 340 G's

...which strikes me as implausible.

That would mean it reaches its burnout velocity of approx 22,000 ft/sec in
two seconds.

Actually, it would do much better than that, since the 340 g is just
the *beginning* acceleration, when it's fully fueled. Just imagine
what it would be as it approaches burnout. ;-)

--
simberg.interglobal.org * 310 372-7963 (CA) 307 739-1296 (Jackson Hole)
interglobal space lines * 307 733-1715 (Fax) http://www.interglobal.org

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