If S = 0.5 a t**2,
and V = at,

Then since S = 55 ft, and V = 1100 ft/sec

a t**2 = 110
and
at = 1100

gives t= 1/10 sec
a = 11000 ft/sec/sec
where g = 32.2 ft/sec/sec
hence a = 340 G's

....which strikes me as implausible.

That would mean it reaches its burnout velocity of approx 22,000 ft/sec in
two seconds.

I don't think so.


"Rusty B" wrote in message
om...
I found a web page on Edwards Air Force Base website that describes
early captive silo test launches of the Minuteman ICBM.

In the article it is claimed that, "a Minuteman passes through Mach
1.0 by the time it travels its own length above the launcher."

A Minuteman I is 55.9-ft tall, A Minuteman III is 59.75-ft tall.

Can anyone verify this claim?

The original article is at this URL:

http://www.edwards.af.mil/moments/do.../59-02-17.html



--
Rusty Barton - Antelope, California |
E-mail - |
Visit my Minuteman ICBM website at: |
http://www.geocities.com/minuteman_missile |