Here is a thought experiment that I am going to modify a little:

http://www.youtube.com/watch?v=xn63xl6GV-E

The travel of one of the spaceships remains unchanged but the acceleration involved in the turn-around will be avoided for the second spaceship. There is a third spaceship which moves with speed v towards the station so that, at the moment the second spaceship was to undergo turn-around and acceleration, the third spaceship passes the second and sets its clock to read the same as the second's. ( This elimination of the acceleration is well known and can be found in textbooks - see 11.19. Modified twin paradox on p. 44 in http://www.people.fas.harvard.edu/~djmorin/chap11.pdf ). Finally, the first and the third spaceships arrive simultaneously at the station. Do their clocks show the same time?

Clever Einsteinians know that both the "yes" and the "no" answers are fatal for relativity. The consequences of Einstein's 1905 false light postulate are inherently contradictory.

Pentcho Valev