Birkoff theorem
On Apr 25, 6:05*pm, Koobee Wublee wrote:
On Apr 25, 3:17 am, waitedavidmsphysics wrote:
** *ds^2 = c^2 (1 – R / u) dt^2 – du^2 / (1 – R / u) – u^2 dO^2
That IS Schwarzschild's solution. What you are calling u everyone else
calls r. When you parameterise u as a function of some other
coordinate like u(r) what you are calling r just isn't what everyone
else on the planet calls r. They are calling what you are calling u as
r.
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