"Koobee Wublee" wrote in message
...
On Mar 28, 9:31 am, Koobee Wublee wrote:
In the meantime, there is only one question. So, here it is again.
Is the following equation valid and correct for the relativistic
Doppler effect?
** f’ / f = (1 + [v] * [c] / c^2) / sqrt(1 – v^2 / c^2)
Where
** [v] = Velocity vector between frames of f and f’
** [c] = Velocity vector of light
** [] * [] = dot product of two vectors
If no, what should be the correct equation for the most general case?
Check out this website because it answers this question. Read it carefully: f_o
is the frequency the receiver measures in his/her rest frame and f_s is the
frequency of the source in the rest frame of the source.
http://en.wikipedia.org/wiki/Relativ...ppler_eff ect
The transverse Doppler effect occurs at theta = 90 degrees.
** f’ / f = 1 / sqrt(1 – v^2 / c^2)
Where
** [v] * [c] / c^2 = 0
This would always indicate a blue shift that does not agree with
experimental observations. shrug
No. The transverse red-shift is given he
http://en.wikipedia.org/wiki/Relativ...ppler_eff ect
The equation is f_o = f_s * sqrt(1 - v^2/c^2) and so f_o is less than f_s. A
lower frequency corresponds to a longer wavelength and so we get:
Lambda_o = Lambda_s / sqrt(1 - v^2/c^2).
So Lambda_o is greater than Lambda_s. What this means is that an observer in the
rest frame of the receiver sees photons emitted by the source at 90 degrees (90
degrees in the rest frame of the receiver) to be red-shifted. But those same
photons would not have been emitted at 90 degrees in the rest frame of the source
due to relativistic aberration. In the rest frame of the source, photons emitted
at 90 degrees will not be emitted at 90 degrees in the rest frame of the
receiver. Those photons will be blue shifted relative to the receiver and that
is explained at he
http://en.wikipedia.org/wiki/Relativ...ry _direction
I truly hope all of this helps.
Einstein Dingleberries cannot weasel out of this one, and the bottom
line is that SR is indeed just garbage. shrug
Not at all.
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