On Mar 28, 9:31 am, Koobee Wublee wrote:

On Mar 29, 6:46 am, PD wrote:

Oh yes, I'm sure. It's awfully easy to confuse the dot product with
the quotient.

So, is this the problem that Einstein Dingleberries do not understand
what dot product is? shrug

http://en.wikipedia.org/wiki/Dot_product

On Mar 29, 9:44 am, Daryl McCullough wrote:

As I have explained to you multiple times, there
are two different questions:
(1) If an electromagnetic wave has frequency f in
one reference frame, then what is its frequency
f' in another reference frame?
(2) If two observers are in relative motion, and the
one observer sends signals at a characteristic rate
of f signals per second, as measured on his own clock,
then what is the rate f' that the other observer will
receive those signals.

These two questions are related, but are not the same.

Bull****! Garbage comments like that show how ignorant Daryl is.
What it looks like is that Daryl is now exhausted with his
permutations of mathematical fudges, and he is desperate to hold on to
his religious belief by throwing **** around. shrug

In the meantime, there is only one question. So, here it is again.
Is the following equation valid and correct for the relativistic
Doppler effect?

** f’ / f = (1 + [v] * [c] / c^2) / sqrt(1 – v^2 / c^2)

Where

** [v] = Velocity vector between frames of f and f’
** [c] = Velocity vector of light
** [] * [] = dot product of two vectors

If no, what should be the correct equation for the most general case?

If yes, WTF is the problem?

For those Einstein Dingleberries who do not understand what dot
product is (including PD and Daryl), the above equation simplifies
into the following.

** f’ / f = (1 + v cos(theta) / c) / sqrt(1 – v^2 / c^2)

Where

** [v] * [c] / c^2 = v cos(theta) / c

The longitudinal Doppler effect if in coming occurs at theta = 0.

** f’ / f = (1 + v / c) / sqrt(1 – v^2 / c^2), in coming

Where

** [v] * [c] / c^2 = v / c

The longitudinal Doppler effect if receding occurs at theta = 180
degrees.

** f’ / f = (1 - v / c) / sqrt(1 – v^2 / c^2), in coming

Where

** [v] * [c] / c^2 = - v / c

The transverse Doppler effect occurs at theta = 90 degrees.

** f’ / f = 1 / sqrt(1 – v^2 / c^2)

Where

** [v] * [c] / c^2 = 0

This would always indicate a blue shift that does not agree with
experimental observations. shrug

Einstein Dingleberries cannot weasel out of this one, and the bottom
line is that SR is indeed just garbage. shrug