"K_h" wrote in message
...
|
| "Koobee Wublee" wrote in message
| ...
| On Mar 28, 3:53 am, Daryl McCullough wrote:
| Koobee Wublee says...
|
| It should be very clear at this stage the Doppler shift no matter
| how
| you fudge it to be should agree with the energy transform as
| described
| below.
|
| ** f' / f = (1 + [v] * [c]) / sqrt(1 - v^2 / c^2)
|
| Look at the obvious problem with this equation. You have V and C as
velocity
| vectors which means their dot product is in units of meters squared per
second
| squared, that is, (m/sec)^2. Then you are adding that to the
dimensionless
| number 1 in your numerator (1+[v]*[c]).

That part is legitimate, simply substitute: c^2/c^2 = 1

c^2/c^2 - v^2/c^2 = (c^2-v^2) /c^2

The difference of two squares is [c+v]*[(c-v], because it equals
c^2 +v*c - v*c - v^2

so

1/beta = sqrt( [c+v]*[(c-v] /c^2) = sqrt(1-v^2/c^2)

It may not be physics, but it is a legitimate algebraic operation.

Chess boards have 63 squares, they measure 7 * 9. Changing the
board enables a checkmate, except that you need a 8 * 8 board or
you are not playing chess.

The problem with Einstein was he never learned mathematics in school,
his "doppler shift" means that moving clocks tick faster to run slow.
t = 1/f
Divide both sides by t,
1 = 1/tf
Multiply both sides by f,
f = 1/t

Now multiply both sides by beta
t * beta = beta/f

but Einstein says
t* beta = 1/ (f*beta)

He then attempts to correct this blunder by frame jumping:

"From the equation for omega' it follows that if an observer is moving with
velocity v relatively to an infinitely distant source of light..."

So now it is the observer that is moving and the distant oscillator is
stationary.
The poor sap was horrendously confused, as are the cretins that can't read
his pathetic algebra because they can't read algebra.