Koobee Wublee says...

On Mar 27, 9:01 am, Daryl McCullough wrote:
On Mar 26, Koobee Wublee wrote:

What is the transverse Doppler effect under relativity?
According to the energy transformation and also your derivation,
it should predict a blue shift while experiments time after time
all have indicated red. Oops! shrug

This disagreement of SR with experiments is serious and fatal, no?

[So] checkmate

Koobee's problem...

It should be very clear at this stage the Doppler shift no matter how
you fudge it to be should agree with the energy transform as described
below.

** f'/f = (1 + [v] * [c]) / sqrt(1 - v^2 / c^2)

Under the transverse case,

** f' / f = 1 / sqrt(1 - v^2 / c^2)

It's kind of funny that you should quote these as evidence that
I'm wrong, when I derived exactly those results. But the transverse
result you give is *NOT* describing how the frequency of an
electromagnetic wave changes under a change of coordinate systems.
Instead, it is a description of the ratio of frequencies of sending
and receiving signals. Why are these not the same thing? Well,
I explained why not, in another post.

The scenario is this: We have two inertial observers, A and B.
According to A's frame, A is at rest at location x=0, y=0.
B is traveling in the +x direction along the line y=L.
A is transmitting signals in the +y direction.

Now, think about it: B is moving perpendicularly to the path
of the signals sent by A. That means that *if* B intercepts
one signal, then the *next* signal will miss him. So if A
is transmitting signals in the y direction, then B is not
going to receive more than one signal, and so will be unable
to measure any kind of frequency at all.

Two ways to rectify this:

(1) You can imagine that instead of just
one sender, there is an *array* of senders, all sending in the
y-direction, all sending in phase. Then if B catches the signal
from one sender, he will catch a different signal from a *different*
sender. In that case, B will see the signals *BLUESHIFTED*.

(2) Instead of A sending in the y-direction, he continually
adjusts his signals so that they always reach B. That means
he has to aim his signals *ahead* of where B is now.

These are *NOT* the same case. In case (2), A is *NOT* transmitting
in the y-direction, the angle is changing with time.

--
Daryl McCullough
Ithaca, NY